The dimensions of coefficient of thermal conductivity is:

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${MLT}^{- 3} K$

$MLT^{- 2} K^{- 1}$

${MLT}^{- 3} K^{- 1}$

${ML}^{2} T^{- 2} K^{- 1}$

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{dQ}{dt} = - KA (\frac{dθ}{dx}) \\ \Rightarrow [K] = \frac{[{ML}^{2} T^{- 2}]}{[T]} \times \frac{[L]}{[L^{2}] [K]} = {MLT}^{- 3} K^{- 1} \end{array}$

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