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Q.

The dimensions of resistivity in terms of M, L, T and Q, where Q stands for the dimensions of charge is

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a

${ML}^{3} T^{- 2} Q^{- 1}$

b

${MLT}^{- 1} Q^{- 1}$

c

${ML}^{3} T^{- 1} Q^{- 2}$

d

${ML}^{2} T^{- 1} Q^{- 1}$

answer is A.

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Detailed Solution

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$R = \frac{V}{I} = [{ML}^{2} T^{- 1} Q^{- 2}] ρ = \frac{RA}{L} ρ = \frac{({ML}^{2} T^{- 1} Q^{- 2}) \times L^{2}}{[L]} = [{ML}^{3} T^{- 1} Q^{- 2}]$

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