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The dimensions of ${(μ_{0} ε_{0})}^{- 1 / 2}$ are

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$[L^{1 / 2} T^{- 1 / 2}]$

$[L^{- 1} T]$

$[{LT}^{- 1}]$

$[L^{- 1 / 2} T^{1 / 2}]$

answer is B.

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Detailed Solution

$∵ {(μ_{0} ε_{0})}^{- 1 / 2} = \frac{1}{{(μ_{0} ε_{0})}^{1 / 2}} = speed of light$

$\Rightarrow [c] = \frac{[L]}{[T]} = [{LT}^{- 1}]$

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