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The diode used in circuit shown in figure has a constant voltage drop of 0.3V at all current and a maximum power rating of 300 milli watt. What should be the value of the resistor R connected in series with the diode for obtaining maximum current

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$1.2 Ω$

$12 Ω$

$2.4 Ω$

$5 Ω$

answer is A.

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Detailed Solution

$T h e c u r r e n t t h r o u g h t h e c i r c u i t i s s a m e c u r r e n t t h r o u g h t h e d i o d e .$

$i = \frac{P}{V} = \frac{300 \times 10^{- 3}}{0.3} = 1 A$

$V o l t a g e d r o p a c r o s s r e s i s \tan c e$

$V_{R} = 1.5 - 0.3 = 1.2 V$

$S o, R = \frac{V_{R}}{i} = \frac{1.2}{1} = 1.2 Ω$

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