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Q.

The diode used in figure requires minimum current of 1mA to be above the knee voltage characteristics. The maximum value of R so that the voltage is above knee point is (Knee voltage of diode is 0.7V)

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a

3.5kΩ

b

4.3kΩ

c

5kΩ

d

5.7kΩ

answer is C.

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Detailed Solution

V−VB=iR   ⇒R=V−VBi

R=5−0.71×10−3=4.3 k Ω

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