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The dip at a place is $δ$ . For measuring it, the axis of the dip needle is perpendicular to the magnetic meridian. If the axis of the dip needle makes angle $θ$ with the magnetic meridian, the tangent of apparent dip will be given $\tan δ_{1}$ , which is equal to

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$\tan δ s e c θ$

$\tan δ \sin θ$

$\tan δ cosec θ$

$\tan δ \cos θ$

answer is B.

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Detailed Solution

$\tan δ = \frac{B_{V}}{B_{H}} and \tan δ_{1} = \frac{B_{V}}{B_{H} cosθ}$

or $\tan δ_{1} = \frac{\tan δ}{\cos θ} = \tan δ \sec θ$

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