The dipole moment of a diatomic molecule is 5.76D and its bond length is 2.5A°. The % of ionic character of the bond is

μ_calculated = dxδ = 2.5x10^-8cmx4.8x10^-10esu
μ_cal = 12x10^-18esu cm = 12D
μ_observed = 5.76D

$$\begin{gathered} \% \mathrm{of} \mathrm{I}.\mathrm{C}=\frac{{\mathrm{\mu }}_{\mathrm{obs}}}{{\mathrm{\mu }}_{\mathrm{cal}}}\times 100 \\ =\frac{5.76\mathrm{D}}{12\mathrm{D}}\times 100 \\ =0.48\times 100=48 \end{gathered}$$
      % I.C = 48%