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The dipole moment of compound A-B was experimentally found to be $1.20 D$ and the bond length is $1.00 A^{0}$ . The percentage of ionic character of bond in A-B is (charge of electron is $4.8 \times 10^{- 10} e s u$ )

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answer is B.

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Detailed Solution

% Ionic character $= \frac{M_{obs}}{M_{cal}} \times 100$

$= \frac{1 .2 D}{4 .8 D} \times 100$

$= 25 %$

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