The disintegration rate of a certain radioactive sample at any instant is 4250 disintegrations per minute. 10 minutes later, the rate becomes 2250 disintegrations per minute. The approximate decay constant is
(Take log₁₀1.88 = 0.274)

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2.7 min^–1

6.3 min^–1

0.02 min^–1

0.063 min^–1

answer is C.

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Detailed Solution

$\begin{array}{l} A_{0} = 4250 \\ A = 2250 = A_{0} e^{- λt} \\ \Rightarrow \frac{2250}{4250} = e^{- λt} \\ \Rightarrow λ (10) = \ln (\frac{4250}{2250}) \\ λ (10) = 0 .636 \\ λ = 0 .063 \end{array}$

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