The displacement equation of a traveling wave pulse, moving along X axis is given by y=8(4+x2)at t = 0, and y=8(x2−10x+29) at t = 1 What is the speed and direction of the pulse ?

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The displacement equation of a traveling wave pulse, moving along X axis is given by $y = \frac{8}{(4 + x^{2})}$ at t = 0, and $y = \frac{8}{(x^{2} - 10 x + 29)}$ at t = 1 What is the speed and direction of the pulse ?

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4 m/s – x axis

2.5m/s + vex

5m/s + x axis

10m/s – x axis

answer is B.

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Detailed Solution

the equation $y = \frac{8}{x^{2} - 10 x + 29} can be written as$

$y = \frac{8}{{(x - 5 t)}^{2} + 4} c = \frac{ω}{k} = \frac{5}{1}$

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