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The displacement of a particle along $x -$ axis is given by $x = 3 + 8 t + 7 t^{2},$ where $x$ is in metres and time $t$ is in seconds. Then its velocity and acceleration at $t = 2 s$ are____________

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$v = 36 m / s$

$v = 14 m / s$

$a = 14 m / s^{2}$

$a = 36 m / s^{2}$

answer is A, C.

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Detailed Solution

$x = 3 + 8 t + 7 t^{2}$
$u = \frac{d x}{d t} = 8 + 14 t$
at $t = 2 s, u = 8 + 14 (2) = 36 m / s$

$a = \frac{d v}{d t} = 14 m / s^{2}$

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