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Q.

The displacement of a particle executing SHM is given by Y=10sin(3t+π3)m where ‘t’ is in seconds. The initial displacement and maximum velocity of the particle are respectively   

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a

53mand30m/sec

b

15mand153m/sec

c

153mand30m/sec

d

203mand30m/sec

answer is A.

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Detailed Solution

Y=Asin(ωt+ϕ)

Y=10sin(3t+π3)

At t=0,Y=10sinπ3=1032=53m

Maximum velocity Vmax=ωA

=10×3

Vmax=30m/s

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The displacement of a particle executing SHM is given by Y=10  sin (3t+π3)m where ‘t’ is in seconds. The initial displacement and maximum velocity of the particle are respectively