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Q.

The displacement of a particle executing SHM is given by y=10sin(3t+π3) m and  't'  is in seconds. The initial displacement and maximum velocity of the particle are respectively,

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a

53m and 30m/sec

b

15m and 15 3 m/sec

c

153m  and 30 m/sec

d

 203m and 30 m/sec

answer is A.

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Detailed Solution

y=A sin (ax=ϕ ).
Given : y=10 sin (3t+π3)  
At t=0, y=10sin  π3=1032
y=53 m
Maximum velocity,  υmax=Aω
=10×3=30m/s
 

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