The displacement of a particle moving in one dimension under a constant force is given by t=x+3 where x is in meters and t is seconds. The work done by the force in first 6 seconds is.

t=x+3⇒x=t−3⇒x=t2+9−6t v=dxdt=2t−6 and a=2 t=0 , V1=−6, t=6, V2=12−6=6W=12m(V22−V12)=12×m(36−36)=0

The displacement of a particle moving in one dimension under a constant force is given by t=x+3 where x is in meters and t is seconds. The work done by the force in first 6 seconds is.

t=x+3⇒x=t−3⇒x=t2+9−6t v=dxdt=2t−6 and a=2 t=0 , V1=−6, t=6, V2=12−6=6W=12m(V22−V12)=12×m(36−36)=0

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The displacement of a particle moving in one dimension under a constant force is given by $t = \sqrt{x} + 3$ where x is in meters and t is seconds. The work done by the force in first 6 seconds is.

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$t = \sqrt{x} + 3 \Rightarrow \sqrt{x} = t - 3 \Rightarrow x = t^{2} + 9 - 6 t v = \frac{d x}{d t} = 2 t - 6 a n d a = 2 t = 0, V_{1} = - 6, t = 6, V_{2} = 12 - 6 = 6$
$W = \frac{1}{2} m (V_{2}^{2} - V_{1}^{2}) = \frac{1}{2} \times m (36 - 36) = 0$

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The displacement of a particle moving in one dimension under a constant force is given by t=x+3 where x is in meters and t is seconds. The work done by the force in first 6 seconds is.

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The displacement of a particle moving in one dimension under a constant force is given by $t = \sqrt{x} + 3$ where x is in meters and t is seconds. The work done by the force in first 6 seconds is.