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Q.

The displacement of a particle varies with time (t) as s = at2 - bt3. The acceleration of the particle will be zero at time t equal to

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a

a/b

b

a/3b

c

3b/a

d

2a/3b

answer is B.

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Detailed Solution

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distance, s = at2 - bt3 
velocity,  v=dsdt=2at3bt2
acceleration a=dvdt=2a6bt
Acceleration is zero at 2a6bt=0t=a3b

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