The displacement of two particles executing S.H.M are represented by y1 = a sin(ωt + ϕ) and y2 = a cosωt. The phase difference between the velocities of these particles is

y1=asin⁡(ωt+ϕ)………(1)phase of it ϕ1=ωt+ϕy2=acos⁡ωt=asin⁡ωt+π2phase of it ϕ2=ωt+π/2phase difference Δϕ=ϕ1−ϕ2=ϕ−π/2

The displacement of two particles executing S.H.M are represented by y1 = a sin(ωt + ϕ) and y2 = a cosωt. The phase difference between the velocities of these particles is

y1=asin⁡(ωt+ϕ)………(1)phase of it ϕ1=ωt+ϕy2=acos⁡ωt=asin⁡ωt+π2phase of it ϕ2=ωt+π/2phase difference Δϕ=ϕ1−ϕ2=ϕ−π/2

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The displacement of two particles executing S.H.M are represented by y₁ = a sin( $ω$ t + $ϕ$ ) and y₂ = a cos $ω$ t. The phase difference between the velocities of these particles is

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$ϕ + π / 2$

$ϕ - π / 2$

$- ϕ$

$+ ϕ$

answer is D.

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$y_{1} = asin (ωt + ϕ) \dots \dots \dots$ (1)
phase of it $ϕ_{1} = ωt + ϕ$
$y_{2} = acos ωt = asin (ωt + \frac{π}{2})$
phase of it $ϕ_{2} = ωt + π / 2$
phase difference $Δϕ = ϕ_{1} - ϕ_{2} = ϕ - π / 2$

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The displacement of two particles executing S.H.M are represented by y1 = a sin(ωt + ϕ) and y2 = a cosωt. The phase difference between the velocities of these particles is

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The displacement of two particles executing S.H.M are represented by y₁ = a sin( $ω$ t + $ϕ$ ) and y₂ = a cos $ω$ t. The phase difference between the velocities of these particles is