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The displacement time graphs of two moving particles make angles of $30° and45°$ with the x – axis. The ratio of the two velocities is

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\sqrt{3} : 1

1 : 2

1 : \sqrt{3}

1 : 1

answer is D.

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Detailed Solution

Slope = [\tan θ] o f \vec{s} - t

Graph gives velocity

$θ_{1} = 30 °, θ_{2} = 45 °$

$\frac{v_{1}}{v_{2}} = \frac{\tan θ_{1}}{\tan θ_{2}}$

$= \frac{\tan 30 °}{\tan 45 °}$

$= \frac{1/ \sqrt{3}}{1} = \frac{1}{\sqrt{3}}$

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