The displacement time graph of a particle executing SHM is given in figure (sketch is schematic and not to scale)

Which of the following statements is/are true for this motion?
(A) The acceleration is maximum at t=2T/4
(B) The speed is maximum at t=3T/4
(C) The PE is equal to KE of the oscillation at t=T/2
(D) The force is zero at t=T/4

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B, C and D

A, B and D

A, B and C

A and D only

answer is A.

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Detailed Solution

A) At t=2T/4, the particle is at extreme position, hence magnitude of acceleration is maximum.
B) At t=3T/4, the particle is at mean position, hence speed is maximum
C) At t=T/2=2T/4, the particle is extreme position, where PE is maximum and KE = 0 ⇒PE≠KE
D) At t=T/4, the particle is mean position, hence force is zero.

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