Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

The displacement time graph of an oscillating particle. Find the maximum velocity  of the particle.

Question Image

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

2 m/s 

b

π m/s

c

2π m/s

d

π2m/s

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For simple harmonic motion, the velocity of a particle is given by  v=Awcoswt .  Hence the maximum velocity of the particle is vmax=Aω . From the graph, time  period of oscillation is 0.2 s. Using the relation  ω=2πT 
Hence,  vmax=Aω=0.22π0.2=2π  ms1
 

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon