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Q.

The displacement x in metres of a particle of mass m kg moving in one dimension under the action of a force is related to the time t in seconds by the equation t = x +3, the work done by the force (in J) in first six seconds is:

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a

zero

b

18 J

c

9 J

d

36 J

answer is B.

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Detailed Solution

Here t = x +3 or x = (t-3)2 = t2-6t+9

v = dxdt = 2t-6

at t = 0, v = 2×0 -6 = -6

at t = 6 s, v = 2×6-6 =+6

Initial and final KE are same hence no work is done.

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