The displacement r¯ of a charge Q in an electric field E=e1i^+e2j^+e3k^ is r¯=ai^+bj^. The work done is

W=Eq⋅r¯=Qe1i+e2j+e3k⋅(ai+bj)=qae1+be2

The displacement r¯ of a charge Q in an electric field E=e1i^+e2j^+e3k^ is r¯=ai^+bj^. The work done is

W=Eq⋅r¯=Qe1i+e2j+e3k⋅(ai+bj)=qae1+be2

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The displacement $\bar{r}$ of a charge Q in an electric field $E = e_{1} \hat{i} + e_{2} \hat{j} + e_{3} \hat{k}$ is $\bar{r} = a \hat{i} + b \hat{j}$ . The work done is

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$Q (e_{1} + e_{2}) \sqrt{a^{2} + b^{2}}$

$(e_{1}^{2} + e_{2}^{2}) (a + b)$

$Q ({ae}_{1} + {be}_{2})$

$Q \sqrt{{({ae}_{1})}^{2} + {({be}_{2})}^{2}}$

answer is A.

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$\begin{array}{l} W = Eq \cdot \bar{r} = Q (e_{1} i + e_{2} j + e_{3} k) \cdot (ai + bj) \\ = q ({ae}_{1} + {be}_{2}) \end{array}$

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The displacement r¯ of a charge Q in an electric field E=e1i^+e2j^+e3k^ is r¯=ai^+bj^. The work done is

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The displacement $\bar{r}$ of a charge Q in an electric field $E = e_{1} \hat{i} + e_{2} \hat{j} + e_{3} \hat{k}$ is $\bar{r} = a \hat{i} + b \hat{j}$ . The work done is