The displacement $\left(x\right)$ of a particle depends on time $t$ as $x=\alpha t^2-\beta t^3$. Choose the incorrect statements from the following.

$x=0$ at $t=0$ and $t=\alpha /\beta$. So, the particle returns to starting point at $t=\alpha /\beta$.
$v=\frac{dx}{dt}=2\alpha t-3\beta t^2$
At $t=0, v=0$ i.e. initial velocity of particle is zero.
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$\nu =0$ at $t=0$ and $t=\frac{2\alpha }{3\beta }$

Thus, the particle comes to rest after time,

$t=2\alpha /3\beta$
$a=\frac{dv}{dt}=2\alpha -6\beta t$
At $t=0,=2\alpha \ne 0$