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The dissociation constant of a weak base is $10^{- 4}$ . The concentration ratio of salt to base to be maintained to keep the $p H$ of buffer solution as 9 is

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1:2

10:1

1:10

2:1

answer is A.

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Detailed Solution

$K_{b} = 10^{- 4}, P^{k b} = 4$

$P^{H} = 9, P^{O H} = 5$

$P^{O H} = P^{k b} + \log [\frac{s a l t}{b a s e}]$

$5 = 4 + \log [\frac{s a l t}{b a s e}]$

$∴ [\frac{s a l t}{b a s e}] = 10$

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