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The dissociation constant of a weak base is $10^{- 4}$ . The concentration ratio of salt to base to be maintained to keep the $P^{H}$ of buffer solution as 9 is

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10:1

1:10

1:2

2:1

answer is A.

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Detailed Solution

$K_{b} = 10^{- 4} P^{K_{b}} = 4$

$P^{H} = 14 - [P^{K_{b}} + \log \frac{[S]}{[B]}]$

$9 = 14 - [4 + \log \frac{[S]}{[B]}]$

$9 = 10 - \log \frac{[S]}{[B]}$

$\log \frac{[S]}{[B]} = 1$

$∴ \frac{[S]}{[B]} = 10 : 1$

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