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Q.

The dissociation of $Al {(OH)}_{3}$ by a solution of NaOH results in the formation of

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a

$[Al {(H_{2} O)}_{3} {(OH)}_{3}]$

b

$[Al {(H_{2} O)}_{6} {(OH)}_{3}]$

c

${[Al {(H_{2} O)}_{2} {(OH)}_{4}]}^{-}$

d

${[Al {(H_{2} O)}_{4} (OH)]}^{2 +}$

answer is A.

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Detailed Solution

$Al {(OH)}_{3} + {OH}^{-} \overset{}{\to} [Al {(OH)}_{4}^{-}]$

Coordination number is 6; thus, it exists as

${[Al {(H_{2} O)}_{2} {(OH)}_{4}]}^{-}$

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