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Q.

The distance between a proton and electron both having a charge 1.6×10−19 coulomb, of a hydrogen atom is 10−10 metre. The value of intensity of electric field produced on electron due to proton will be

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a

14.4 V/m

b

2.304×10−10 N/C

c

16 V/m

d

1.44×1011 N/C

answer is D.

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Detailed Solution

E=q4πε0r2=9×109×1.6×10−1910−102=1.44×1011 N/C

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