The distance between the centres of carbon and oxygen atoms in the carbon  monoxide gas molecule is $1.12 \times {10}^{-10}\mathrm{m}$. The distance of centre of mass of the molecule relative to carbon atom is

Let the masses of the carbon and oxygen atoms, $m_1$ and $m_2$, be the same. Let d represent the spacing between the carbon and oxygen atoms' centres.
Let the positions of the carbon atom in $x_1$ and the oxygen atom in $x_2$ be given.
The system's centre of mass can be expressed as follows:

${\mathrm{x}}_1=0\mathrm{m}, {\mathrm{x}}_2=1.12\times {10}^{10}\mathrm{m}$

${\mathrm{m}}_1=12\mathrm{U}, {\mathrm{m}}_2=16\mathrm{U}$

${\mathrm{x}}_{\mathrm{CM}}=\frac{12\times 0+16\times 1.12\times {10}^{-10}}{12+16}=6.4\times {10}^{-11}\mathrm{m}=0.64\times {10}^{-10}\mathrm{m}$

Hence the correct answer is $0.64\times {10}^{-10}\mathrm{m}.$