The distance between the centres of carbon and oxygen atoms in the carbon monoxide gas molecule is  $1.12\times {10}^{-10}m$ . The distance of centre of mass of molecule relative to carbon atom is  $\_\_\_\_\_\times {10}^{-12}m$ 

Let the masses of the carbon and oxygen atoms, m₁ and m₂, be the same. Let d represent the spacing between the carbon and oxygen atoms centres.
Let the positions of the carbon atom in x₁and the oxygen atom in x₂ be given.
The system's centre of mass can be expressed as follows:

$\begin{array}{l}{\mathrm{x}}_1=0\mathrm{m},{\mathrm{x}}_2=1.12\times {10}^{10}\mathrm{m}\\ {\mathrm{m}}_1=12\mathrm{U},{\mathrm{m}}_2=16\mathrm{U}\\ {\mathrm{x}}_{\mathrm{CM}}=\frac{12\times 0+16\times 1.12\times {10}^{-10}}{12+16}=6.4\times {10}^{-11}\mathrm{m}=64\times {10}^{-12}\mathrm{m}\end{array}$