The distance between the circumcentre and the orthocentre of the triangle formed by the points (2, 1, 5), (3, 2, 3) and (4, 0, 4) is

Let A(2, 1, 5), B(3, 2, 3) and C(4, 0, 4) are vertices of a triangle

AB=BC=CA=$\sqrt{6}$

$\therefore$The triangle formed by the given points is an equilateral triangle.

$\therefore$circum centre = ortho centre

$\therefore$The distance between the circumcentre and the orthocentre of the triangle  is 0