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Offline Centres

The distance between the orthocentre and the circumcentre of the triangle with vertices (0, 0),(0, $a$ ) and ( $b$ , 0) is

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$a + b$

$\sqrt{a^{2} + b^{2}} / 2$

$\sqrt{a^{2} - b^{2}} / 2$

$a - b$

answer is D.

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Detailed Solution

The triangle is right angled at (0, 0) so the orthocentre
is (0, 0) and circumcentre is $(a / 2, b / 2),$ the mid point
of the hypotenuse.

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