Q.

The distance between the parallel lines 4y2x+1=0,x2y+1=0 is

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a

23

b

325

c

112

d

45

answer is A.

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Detailed Solution

2x4y1=0

2x4y+2=0

Formulae: Distance between parallel lines =|c1c2|a2+b2

Distance between parallel lines =|1+2|4+16=325.

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The distance between the parallel lines 4y−2x+1=0, x−2y+1=0 is