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Q.

The distance between the plates of a parallel plate capacitor is d. A metal plate of thickness d / 2 is placed between the plates. The capacitance would then be

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a

Unchanged

b

Halved

c

Zero

d

Doubled

answer is D.

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Detailed Solution

$C = \frac{ε_{0} A}{d - (d / 2)} = 2 \frac{ε_{0} A}{d}$

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