The distance between the poles of a horse shoe magnet is 0.1 m and its pole strength is 0.01 Am. The induction of magnetic field at a point midway between the poles will be

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$4 x 10^{- 6} T$

$2 x 10^{- 5} T$

Zero

$8 x 10^{- 7} T$

answer is C.

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Detailed Solution

Net magnetic field at mid point P, $B = B_{N} + B_{S}$

where $B_{N}$ = magnetic field due to N-pole

$B_{S}$ = Magnetic field due to S-pole

$B_{N} = B_{S} = \frac{μ_{0}}{4 π} \frac{m}{r^{2}}$

$= 10^{- 7} x \frac{0.01}{{(\frac{0.1}{2})}^{2}} = 4 x 10^{- 7} T$

$∴ B_{net} = 8 x 10^{- 7} T$

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