The distance between two bodies becomes 6 times of actual distance. Then the force becomes

$$\begin{gathered} We know that \\ F=\frac{G{m}_1{m}_2}{r^2} \\ \Rightarrow F\propto \frac{1}{r^2} \\ \Rightarrow \frac{F_1}{F_2}=\frac{{r_2}^2}{{r_1}^2} \\ {r}_2=6r_1 \\ \Rightarrow \frac{F_1}{F_2}=\frac{{\left(6r_1\right)}^2}{{r_1}^2} \\ \Rightarrow \frac{F_1}{F_2}=\frac{36{r_1}^2}{{r_1}^2} \\ \Rightarrow \frac{F_1}{F_2}=\frac{36}{1} \\ \Rightarrow F_2=\frac{F_1}{36}=\frac{1}{36}timesofinitial \end{gathered}$$