The distance between two bodies becomes 6 times the usual distance. Then F becomes

the gravitational force between any two bodies that have some mass is given as:

${\text{F}}_{ }=\text{G}.\frac{{\text{m}}_{\text{1}}{\text{m}}_{\text{2}}}{{\text{r}}_{ }^2}$
Where m₁ and m₂ are the masses of the two bodies, r is the distance between them and G is the universal gravitation constant.
$G= 6.67 X {10}^{-11} N{m}^2/k{g}^2$

$F\propto \frac{1}{r^2}$
 $F_2=G\frac{m_1{m}_2}{{\left(6r\right)}^2}$

$F_2= \frac{F_1}{36}$

Hence option D is the correct answer.