The distance of centre of mass from 5 kg body is 

Given that

${\mathrm{m}}_1=5\mathrm{kg},{\mathrm{m}}_2=4\mathrm{kg},{\mathrm{m}}_3=6\mathrm{kg}$

${\mathrm{r}}_1=0,{\mathrm{r}}_2=0.3,{\mathrm{r}}_3=0.3+0.7=1\mathrm{m}$

Consider origin and coordinate axis at 5kg mass then (with respect to 5kg)

${\mathrm{r}}_{\mathrm{cm}}=\frac{{\mathrm{m}}_1{\mathrm{r}}_1+{\mathrm{m}}_2{\mathrm{r}}_2+{\mathrm{m}}_3{\mathrm{r}}_3}{{\mathrm{m}}_1+{\mathrm{m}}_2+{\mathrm{m}}_3}$

$=\frac{5\left(0\right)+4\left(0.3\right)+6\left(1\right)}{5+4+6}=\frac{7.2}{15}=0.48\mathrm{m}$