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Q.

The distance of neptune and saturn from sun are nearly 10¹³ and 10¹² meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio

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a

$10 \sqrt{10}$

b

$\sqrt{10}$

c

$100$

d

$1 / \sqrt{10}$

answer is C.

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Detailed Solution

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$\frac{T_{1}}{T_{2}} = {(\frac{R_{1}}{R_{2}})}^{3 / 2} = {(\frac{10^{13}}{10^{12}})}^{3 / 2} = (1000)^{1 / 2} = 10 \sqrt{10}$

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