The distance s (in m) travelled by a particle is given by the expression 4s=5t2+8t, here t is time in seconds. The acceleration of the particle is

v=dsdt=1410t+8a=dvdt=1410=2.5 m/s2

v=dsdt=1410t+8a=dvdt=1410=2.5 m/s2

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The distance s (in m) travelled by a particle is given by the expression 4s=5t²+8t, here t is time in seconds. The acceleration of the particle is

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2 ms^-2

5 ms^-2

2.5 ms^-2

1.25 ms^-2

answer is B.

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$v = \frac{ds}{dt} = \frac{1}{4} (10 t + 8)$

$a = \frac{d v}{dt} = \frac{1}{4} (10) = 2.5 m / s^{2}$

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