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The distance travelled by a falling body in the last second of its motion, to that in the last but one second is 7 : 5, the velocity with which body strikes the ground is

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19.6m/s

29.4m/s

49m/s

39.2m/s

answer is B.

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Detailed Solution

$\frac{\frac{g}{2} (2 n - 1)}{\frac{g}{2} (2 (n - 1) - 1)} = \frac{7}{5}$

n = 4 sec ;

$h = \frac{1}{2} {gn}^{2} = \frac{g}{2} \times 16 = 8 g V = \sqrt{2 gh} = \sqrt{2 g \times 8 g}$

= 4 x g = 4 x 9.8 = 39.2m/sec

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