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The distance travelled by a particle in time 't' is given by $S = 6 t^{3} - 2 t^{2} - 3 t + 2$ . The velocity of the particle when t =1 seconds is

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7 $u n i t / \sec$

3 $u n i t / \sec$

11 $u n i t / \sec$

$1 / 2 u n i t / \sec$

answer is A.

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Detailed Solution

$s = 6 t^{3} - 2 t^{2} + 2 - 3 t$

$v = 18 t^{2} - 4 t - 3$

$t = 1, v = 18 - 4 - 3 = 11$

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