The divisor when the quotient, dividend and the remainder are respectively 547, 171282 and 71 is equal toSub Grade:

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The divisor when the quotient, dividend and the remainder are respectively 547, 171282 and 71 is equal to

Sub Grade:

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333

323

313

303

answer is C.

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Detailed Solution

Let x be the divisor
Formula , dividend = divisor quotient + remainder
= 171282= x*547+71
= 171282= 547x+71
= 171282-71= 447 x
x= 171211/547 = 313

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