Q.

 The domain of definition of the function f(x)=1+loge(1-x)

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a

-<x0

b

-<xe-1e

c

-<x1

d

x1-e

answer is B.

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Detailed Solution

f(x)=1+loge(1x) value of f(x) is real when 1+loge(1x)0 and 1x>0loge(1x)1 and x<1loge(1x)1 and x<11x1e and x<1xe1e and x<1 . 

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 The domain of definition of the function f(x)=1+loge(1-x)