The donor sites of $(EDTA)^{4}$ are ?

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Two N atoms and four O atoms

O atoms only

N atoms only

Three N atoms and three O atoms

answer is C.

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Detailed Solution

The four negatively charged O atoms and the two positively charged N atoms in $(EDTA)^{4}$ are the donor atoms. Because a single $(EDTA)^{4}$ ion establishes six bonds to the Fe atom in this combination.

Hence, the correct option is C.

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