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Q.

The driver of a 1200 kg car notices that the car slows from 20 m/s to 15 m/s as it covers a distance of 125 m along level ground. How large a force opposes the motion?

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a

125 N

b

540 N

c

1240 N

d

840 N

answer is D.

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Detailed Solution

According to work-energy theorem

$\begin{array}{l} W = F . S = \frac{1}{2} m (v^{2} - u^{2}) \\ F = \frac{1200 \times (400 - 225)}{2 \times 125} = 840 N \end{array}$

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