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Q.

The driver of a car approaching a vertical wall notices that the frequency of the horn of his car changes from 400 Hz to 450 Hz after being reflected from the wall. Assuming speed of sound to be 340 m/s, the speed of approach of car towards the wall is

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a

30 m/s

b

20 m/s

c

40 m/s

d

10 m/s

answer is B.

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Detailed Solution

$\begin{array}{l} 450 = 400 (\frac{340 + v_{s}}{340 - v_{s}}) \\ \Rightarrow \frac{9}{8} = \frac{340 + v_{s}}{340 - v_{s}} \\ \Rightarrow 9 (340) - 9 v_{s} = 8 (340) + 8 v_{s} \\ \Rightarrow 17 v_{s} = 340 \\ \Rightarrow v_{s} = 20 m / s . \end{array}$

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