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Q.

The dye acriflavine when dissolved in water has its maximum light absorption at 4530A0  and has maximum florescence emission at  5080A0. The number of fluorescence quanta is about 53% of the number of quanta absorbed. What percentage of absorbed light energy is emitted as fluorescence?(round off to the nearest integer)

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answer is 47.

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Detailed Solution

Eabs×x100=Eemit⇒n1.hcλ1.x100=n2.hcλ2 ∴            x=n2n1×λ1λ2=53100×45305080=47.3

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