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$\large Z{n_{\left( s \right)}} + \,C{l_2}\left( {1atm} \right)\, \to \,Z{n^{2 + }} + 2C{l^ - }$

The E⁰ of the cell is 2.12 V. To increase E

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Partial preassure of Cl₂ should be decreased.

Zn²⁺ concentration should be increased

Cl^– concentration should be increased

Zn²⁺ concentration should be decreased

answer is B.

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Detailed Solution

According to Nernst Equation

$E_{cell}\;={E_{cell}^o}-\frac{0.0591}{2}\;log\frac{[Zn^{+2}][Cl^{-}]^{2}}{p{_{Cl_{2}}}}$

$E_{cell}\;=2.12-\frac{0.0591}{2}\;log\frac{[Zn^{+2}][Cl^{-}]^{2}}{1}$

$E_{cell}\propto\;-\log{[Zn^{+2}][Cl^{-}]^{2}}$

Decrease in concentration of [Zn]⁺² and [Cl]^-will increase E_cell.

Special note

when all concentrations are constant

$E_{cell}\propto\;-\frac{1}{p_{Cl_{2}}}$

When pressure of Cl₂increases E_cellincreases.

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