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The EAN of platinum in potassium hexachloridoplatinate (IV) is :

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answer is B.

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Detailed Solution

$EAN = z -$ Oxidation state $+ 2 \times x$

Where z is Atomic number, x is Coordination number and EAN is effective atomic number

EAN value of platinum is,

$\begin{array}{l} E A N = 78 - 4 + 12 \\ E A N = 86 \end{array}$

Hence correct option is B.

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