The earth (mass $= 6 \times 10^{24} kg)$ ) revolves round the sun with angular velocity $2 \times 10^{- 7} rad / s$ in a circular orbit of radius $1 .5 \times 10^{8} km$ . The force exerted by the sun on the earth in newtons, is

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$18 \times 10^{25}$

$36 \times 10^{21}$

$27 \times 10^{39}$

Zero

answer is D.

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Detailed Solution

$m = 6 \times 10^{24} kg, ω = 2 \times 10^{- 7} rad / s, R = 1 .5 \times 10^{11} m$

The force exerted by the sun on the earth $F = {mω}^{2} R$
By substituting the value we can get, $F = 36 \times 10^{21} N$

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