The earth receives 8.4 J/minute/m2 energy from the sun. If the solar energy in 10×104m2 area is concentrated in a cup filled with 100 g water at 00C . The time during which water will boil (in sec) is:

Energy received by sun = 8.4 J/min−mt2Area = 10×104mt2 ∴ 8.4×10560=msΔθt=8.4×10560 =0.1×4200×100tOn solving t=3 s

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The earth receives $8.4 J / minute / m^{2}$ energy from the sun. If the solar energy in $10 \times 10^{4} m^{2}$ area is concentrated in a cup filled with 100 g water at $0^{0} C$ . The time during which water will boil (in sec) is:

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Energy received by sun = $8.4 J / \min - m t^{2}$
Area = $10 \times 10^{4} m t^{2}$

$∴ \frac{8.4 \times 10^{5}}{60} = \frac{m s Δ θ}{t}$

$= \frac{8.4 \times 10^{5}}{60} = \frac{0.1 \times 4200 \times (100)}{t}$

On solving

$t = 3 s$

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